6x(x-7)=(13x^2)-43x

Solution for 6x(x-7)=(13x^2)-43x equation:

6x(x-7)=(13x^2)-43x

We move all terms to the left:

6x(x-7)-((13x^2)-43x)=0

We multiply parentheses

6x^2-42x-(13x^2-43x)=0

We get rid of parentheses

6x^2-13x^2-42x+43x=0

We add all the numbers together, and all the variables

-7x^2+x=0

a = -7; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-7)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-7}=\frac{-2}{-14}
=1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-7}=\frac{0}{-14}
=0
$